Prove a Pointer Holds x's Address

x, y and the pointer p (aimed at x) are declared for you. Print the two comparisons p == &x and p == &y with %d. Do not print raw addresses.

Print exactly what is shown in Expected Output.

Expected Output:

p == &x: 1↵
p == &y: 0↵

= newline. The output ends with a newline — print one after the last line.

Hints2 available

Topics:

Pointers

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