Allocate a Label Through a char ** Out-Parameter

Complete this function (the signature is given and must not change):

void make_label(const char *name, int count, char **out)

It must allocate a new string holding name, then  x , then count — for example bolts and 7 produce bolts x 7 — and store that pointer in *out.

In main, read a word and an integer from input (separated by a space), call make_label, then print two lines: Label:  followed by the string, and Length:  followed by the number of characters in that string.

For the input:

bolts 7

the output is exactly what is shown in Expected Output.

Each line ends with a newline. The word is never longer than 31 characters.

Free the memory you allocate before the program ends — this question checks for memory leaks.