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Question 260
Width and Precision
Width and Precision
A valuex = 3.14159is given. Print it rounded to 2 decimals, right-aligned in a field 8 characters wide, surrounded by|(see Expected Output). That is 4 spaces then3.14. Combine width and precision as%8.2f.
Expected Output:
| 3.14|= newline. No newline after the last line.
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