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Width and Precision

A value x = 3.14159 is given. Print it rounded to 2 decimals, right-aligned in a field 8 characters wide, surrounded by | (see Expected Output).

That is 4 spaces then 3.14. Combine width and precision as %8.2f.

Expected Output:

|    3.14|

= newline. No newline after the last line.

Hints2 available
Topics:
Printing
1
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