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Count Odd Numbers

An array called nums has already been created for you with the values {10, 15, 20, 25, 30}. A variable called count has been initialized to 0.

Your task is to use the for loop to count how many odd numbers are in the array.

A number is odd if dividing it by 2 leaves a remainder of 1. You can check this using: nums[i] % 2 != 0. The % operator gives the remainder: if it's not 0, the number is odd.

In this array, the odd numbers are 15 and 25, so the count should be 2.

Print the result in the exact format shown in Expected Output.

Expected Output:

Odd count: 2

= newline. No newline after the last line.

Hints2 available
Topics:
Arrays
1
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Your Output

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Test Cases

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