Prove the Pointer Holds the Right Address

Two ints x and y are declared and p already points at x. The value check on the last line is written for you. Print the two address comparisons.

p == &x: 1↵
p == &y: 0↵
*p == x: 1↵

= newline. The output ends with a newline — print one after the last line.

Hints2 available

Topics:

Pointers

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