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Question 744
ArgumentNullException
ArgumentNullException
Read one line. Treat the literal textnullas a null string. If the value is null,throw new ArgumentNullException("name"); otherwise printHi <name>. Catch theArgumentNullExceptionand printName is required. Use top-level statements. InputBobprints: Hi Bob Inputnullprints: Name is required
Expected Output:
Hi Bob= newline. The output ends with a newline — print one after the last line.
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