Identify The Exception Type

Read an integer n. If n == 0, throw a DivideByZeroException; if n < 0, throw an ArgumentException; otherwise print Value: <n>. Use a single catch (Exception ex) that catches any of them and prints Caught: <ex.GetType().Name>. Use top-level statements.

Input 5 prints: Value: 5
Input 0 prints: Caught: DivideByZeroException
Input -1 prints: Caught: ArgumentException

Expected Output:

Value: 5↵

= newline. The output ends with a newline — print one after the last line.

Hints4 available

Topics:

Exceptions

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