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Question 42
Character Option Validator
Character Option Validator
Create aninputCharOption()method that accepts a Scanner and a String of valid characters. It should: 1. Read input usingnextLine()2. Check if input is exactly 1 character AND is in the validChars string 3. If valid, return the character 4. If invalid, print "ERROR: Character must be one of [validChars]: " and try again Inmain(), use it to get Y or N, then display: You entered: [character] Example: If user enters "a", "n", then "N", output shows errors then prints the output shown in Expected Output. ⚠️ IMPORTANT - AUTO-INPUT MODE: This question uses automated input testing. When you run your code, the input stream will AUTOMATICALLY contain: 'N\n' DO NOT wait for manual keyboard input - Scanner will read from the pre-filled buffer stream immediately. Your validation loop should usescanner.nextLine()to read input. Think of it like Eclipse/VS Code but with the input already typed in and waiting for your Scanner to read it.
Expected Output:
You entered: N= newline. The output ends with a newline — print one after the last line.
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