Digit Sum

Read a positive whole number and add up its digits with a while loop: the remainder operator % with 10 peels off the last digit and integer division // by 10 removes it; keep going while the number is above 0. Print Digit sum: <total>. Input: one integer, no prompt.

Expected Output:

Digit sum: 10↵

= newline. The output ends with a newline — print one after the last line.

Hints3 available

Topics:

Loops

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