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Question 591
Step Countdown By Recursion
Step Countdown By Recursion
Complete count_down_by(n: int, step: int) -> None so it prints n, then n - step, then n - 2 * step and so on, one number per line, stopping before the first value that is 0 or below (that value is not printed), using recursion. The base case is written: a value of 0 or less prints nothing. Add the recursive case, which prints n and then calls the function with n - step and the same step. Do NOT write a main block or any top-level test code; the tests construct the calls. Input: two lines, n then step, no prompts, which the tests read and pass to your function.
Expected Output:
10 7 4 1
= newline. The output ends with a newline — print one after the last line.
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