Even Or Odd Word

Write the body of parity(num: int) -> str so it returns the word even when the number divides by 2 with nothing left over and odd otherwise. The remainder operator % gives the leftover of a division, so num % 2 is 0 exactly for even numbers. Do NOT write a main block or any top-level test code; the tests construct the calls. Input: one line, an integer, which the tests read and pass to your function before printing the word it returns.